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There is always a 1 to 1 correspondence between the number guanines (G) and the number of cytosines (C) in a DNA molecule. The same is true of the relationship between adenine (A) and thymine (T). Of course Professor Floop knows this. He analyzed a strand of DNA and determined the amounts of C and G it contained. If the molecule was 22% G, what was the percentage of A, assuming that DNA only contains G, C, A, and T

User RodeoClown
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1 Answer

3 votes

Answer:

the strand contains 28% of adenine.

Explanation:

We have only four components, and we only know one of them:


\left[\begin{array}{cc}C&?\\G&22\%\\A&?\\T&?\end{array}\right]

Cytosine has a relation 1 to 1 with G, therefore the strand must contain the same amount of C as it posses G:


\left[\begin{array}{cc}C&22\%\\G&22\%\\A&?\\T&?\end{array}\right]

Therefore:


A + T = 100\% - (C+G)

This is because the strain only contains those 4 components.

since A and T have also a 1 to 1 relation, we can state that A = T in quantity.

So:


A + A = 100\% - (C+G)


2A = 100\% - (22\%+22\%)


A = (100\%-44\%)/(2)


A = (56%)/(2)


A = 28\%

User Berbie
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