Answer: 374416
Explanation:
Given : A test requires that you answer first Part A and then either Part B or Part C.
Part A consists of 4 true false questions, Part B consists of 6 multiple-choice questions with one correct answer out of five, and Part C consists of 5 multiple-choice questions with one correct answer out of six.
i.e. 2 ways to answer each question in Part A.
For 4 questions, Number of ways to answer Part A =
![2^4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7n6j78uc4hd2a6gvxgc9vto41qtn17clxm.png)
5 ways to answer each question in Part B.
For 6 questions, Number of ways to answer Part B =
![5^6](https://img.qammunity.org/2020/formulas/mathematics/college/2a6ma7lgzhnpe94tqommuwm0cw0mc4mxck.png)
6 ways to answer each question in Part C.
For 5 questions, Number of ways to answer Part C =
![6^5](https://img.qammunity.org/2020/formulas/mathematics/college/wgiounqqpsur898teqi5li0b0yg4y5hd5o.png)
Now, the number of ways to completed answer sheets are possible :_
![2^4*5^6+2^4*6^5\\\\=2^4(5^6+6^5)\\\\=16(15625+7776)\\\\=16(23401)=374416](https://img.qammunity.org/2020/formulas/mathematics/college/9rzbuy7ke0i833bb0p9a5m23habdm8uq6i.png)
Hence, the number of ways to completed answer sheets are possible = 374416