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A steel rectangular tube has outside dimensions of 150 mm x 50 mm and a wall thickness of 4 mm. State the inside dimensions, the area of its cross section, and the weight of a piece 1.22 m long.

User Mayya
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1 Answer

7 votes

Answer:

inside dimension
= 142 mm * 42 mm

cross section area
= 7.5* 10^(-3) m^2

mass of 1.2 meter log steel
= 1.843* 10^(-3) \rho

Step-by-step explanation:

given data:

Outside dimension of steel rectangular
= 150 mm* 50mm

Thickness = 4 mm

Long = 1.22 m

inside dimension will be
= (150- 8)mm * ( 50-8)mm


= 142 mm * 42 mm

cross section area
= 150* 50 mm^2


= 7500* 10^(-6) m^2


= 7.5* 10^(-3) m^2

let the density be assumed as \rho

mass of 1.2 meter log steel will be
= 1.2  * (7.5* 10^(-3) -  0.142* 0.048)* \rho


= 1.843* 10^(-3) \rho

User Issa Fram
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