Question

Jerry knocks a flowerpot off its third-story ledge, 9.5 m above the ground. If it falls freely, how fast is the flowerpot moving when it crashes to the sidewalk?

Answer 1

13.65 m/s

Step-by-step explanation:

t = Time taken

u = Initial velocity = 0

v = Final velocity

s = Displacement = 9.5 m

a = Acceleration = 9.81 m/s²

`v^2-u^2=2as\\\Rightarrow v=√(2as-u^2)\\\Rightarrow v=√(2* 9.81* 9.5-0^2)\\\Rightarrow v=13.65\ m/s`

The flower pot is moving at a speed of 13.65 m/s when it crashes the sidewalk.