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You throw a ball straight down from an apartment balcony to the ground below. The ball has an initial velocity of 5.10 m/s, directed downward, and it hits the ground 1.92 s after it is released. Find the height of the balcony.

User Sridarshan
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1 Answer

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Answer:

the height of the balcony from where the ball is thrown is 27.874 m.

Step-by-step explanation:

given,

initial velocity (u) = 5.1 m/s

time (t) = 1.92 s

height of balcony = ?

using equation;


s = u t + (1)/(2) at^2


h =5.1 * 1.92 + (1)/(2)* 9.81* 1.92^2

h= 9.792 + 18.082

h = 27.874 m

hence, the height of the balcony from where the ball is thrown is 27.874 m.

User Judyta
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