Answer:
the height of the balcony from where the ball is thrown is 27.874 m.
Step-by-step explanation:
given,
initial velocity (u) = 5.1 m/s
time (t) = 1.92 s
height of balcony = ?
using equation;
![s = u t + (1)/(2) at^2](https://img.qammunity.org/2020/formulas/physics/college/w29lxu4dl0e734xx7wilz9pyhnizch8ui9.png)
![h =5.1 * 1.92 + (1)/(2)* 9.81* 1.92^2](https://img.qammunity.org/2020/formulas/physics/college/86w7m1ot2vkku1borngnnnqty3q6g36qjo.png)
h= 9.792 + 18.082
h = 27.874 m
hence, the height of the balcony from where the ball is thrown is 27.874 m.