Question

Suppose a group consists of 5 students. Three students are selected at random to do a presentation. How many different sets of presenters are possible?

Answer 1

The number of presentation groups of 3 students that can be selected from a group of 5 students equals 10.

Step-by-step explanation:

The number of different presenters equals the no of possible combinations of 3 students from a pool of 5 students.

Thus the number of possible combinations equals

`\binom{5}{3}=(5!)/((5-3)!* 3!)=10`