Question

What is the magnitude of the electric field at a distance of 89 cm from a 27 μC charge, in units of N/C?

Answer 1

306500 N/C

Step-by-step explanation:

The magnitude of an electric field around a single charge is calculated with this equation:

`E(r) = (1)/(4 \pi *\epsilon 0) (q)/(r^2)`

With ε0 = 8.85*10^-12 C^2/(N*m^2)

Then:

`E(0.89) = (1)/(4 \pi *8.85*10^-12) (27*10^-6)/(0.89^2)`

E(0.89) = 306500 N/C