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To lift an objet weighing 21,000N, how much force is needed on a piston with an area of 0.060 meters squared if the platform being lifted has an area of 3.0 meters squared?

User Mansu
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1 Answer

4 votes

Answer:

The weight required on the piston equals 420 Newtons.

Step-by-step explanation:

from the principle of transmission of pressure in a hydraulic lift we have


(F_(1))/(A_(1))=(F_(2))/(A_(1))

where

'F' is the force that acts on the piston

'A' is the area of the piston.

Since the force in the question is 21000 Newtons thus upon putting the values in the above equation we get


(21000)/(3.0m^(2))=(W)/(0.06m^(2))

Solving for
W we get


W=(21000)/(3)* 0.06\\\\\therefore W=420Newtons

User Olemarius
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