Question

What magnitude charge creates a 1.70 N/C electric field at a point 4.60 m away? Express your answer with the appropriate units.

Answer 1

`Q=4.0*10^(-9)C`

Step-by-step explanation:

Electric field of a charge:

`E=k*(Q)/(R^(2))`

`Q=(E*R^(2))/(K)=1.7*4.6^(2)/(9*10^(9))=4.0*10^(-9)C`