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What magnitude charge creates a 4.80 N/C electric field at a point 3.60 m away?
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What magnitude charge creates a 4.80 N/C electric field at a point 3.60 m away?

User MarcoZen
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5.3k points

1 Answer

2 votes

Answer:

Q = 6.9 X 10⁻⁹ C.

Step-by-step explanation:

Electric field E due to a charge Q at distance r is given by the relation

E = k Q / r²

Here E = 4.8 , k = 9 x 10⁹ ; r = 3.6 m Q = ?

4.8 =
(9*10^9* Q)/((3.6)^2)

Q =
(4.8*(3.6)^2)/(9*10^9)

Q = 6.9 X 10⁻⁹ C.

User DL Narasimhan
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5.1k points
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