Question

What is the volume (in dm3 of 1 mole of oxygen at 5 MPa and 200 K?

Answer 1

Answer: The volume of oxygen gas is
`0.332dm^3`

Step-by-step explanation:

To calculate the volume of the gas, we use the equation given by ideal gas equation:

`PV=nRT`

where,

P = pressure of the gas = 5 MPa = 5000 kPa (Conversion factor: 1 MPa = 1000 kPa)

V = Volume of gas = 3.34 L

n = number of moles of oxygen gas = 1 mole

R = Gas constant =
`8.31dm^3\text{ kPa }mol^(-1)K^(-1)`

T = Temperature of the gas = 200 K

Putting values in above equation, we get:

`5000kPa* V=1mol* 8.31dm^3\text{ kPa }mol^(-1)K^(-1)* 200K\\\\V=0.332dm^3`

Hence, the volume of oxygen gas is
`0.332dm^3`