Question

How much power (energy per unit time) can be provided by a 75 m high waterfall with a flow rate of 10,000 L/s? Give answer in kW rate given here is volume per unit time; 10,000 L/s mean that every second 10,000 L of water go through the water fall

Answer 1

Step-by-step explanation:

It is given that flow rate is 10,000 L/s. As 1 L equals 0.001
`m^(3)`.

Hence, flow rate will be 10
`m^(3)/s`. Calculate mass of water flowing per second as follows.

Mass flowing per second = density × flow rate

=
`1000 kg/m^(3) * 10 m^(3)/s`

=
`10^(4) kg/s`

Also, energy provided per second will be as follows.

E = mgh

Putting the given values into the above formula as follows.

E = mgh

=
`10^(4) kg/s * 9.8 m/s^(2) * 75 m`

=
`735 * 10^(4) W`

or, = 7350 kW

Thus, we can conclude that energy per unit time provided will be 7350 kW.