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How much power (energy per unit time) can be provided by a 75 m high waterfall with a flow rate of 10,000 L/s? Give answer in kW rate given here is volume per unit time; 10,000 L/s mean that every second 10,000 L of water go through the water fall

User Eithos
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1 Answer

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Step-by-step explanation:

It is given that flow rate is 10,000 L/s. As 1 L equals 0.001
m^(3).

Hence, flow rate will be 10
m^(3)/s. Calculate mass of water flowing per second as follows.

Mass flowing per second = density × flow rate

=
1000 kg/m^(3) * 10 m^(3)/s

=
10^(4) kg/s

Also, energy provided per second will be as follows.

E = mgh

Putting the given values into the above formula as follows.

E = mgh

=
10^(4) kg/s * 9.8 m/s^(2) * 75 m

=
735 * 10^(4) W

or, = 7350 kW

Thus, we can conclude that energy per unit time provided will be 7350 kW.

User Mathisonian
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