Question

Determine the Darcy friction factor for a fluid flowing in a pipe with diameter 0.01 metres, flowing at 0.03 m/s. The fluid density is 36.4 kg/m and viscosity is 0.651 Pa*s. The pipe absolute roughness is 0.00062459 m. Give your answer rounded to the nearest whole number.

Answer 1

Step-by-step explanation:

The given data is as follows.

Diameter of pipe, D = 0.01 m

Velocity V = 0.03 m/s

Fluid density = 36.4
`kg/m^(3)`

Viscosity = 0.651 Pa-s

Formula to calculate Reynold number is as follows.

Re =
`diameter * velocity * (density)/(viscosity)`

=
`0.01 * 0.03 * (36.4)/(0.651)`

= 0.01677

Since, Re < 2100. This means that the flow is laminar.

So, for laminar flow in pipes,

Darcy friction factor f =
`(64)/(Re)`

=
`(64)/(0.01677)`

= 3816

Thus, we can conclude that the Darcy friction factor value is 3816.