Question

How many joules are required to raise the temperature of a cubic meter of water by 10K?

Answer 1

4.186 × 10⁷ J

Step-by-step explanation:

Heat gain by water = Q

Thus,

`m_(water)* C_(water)* \Delta T=Q`

For water:

Volume = 1 m³ = 1000 L ( as 1 m³ = 1000 L)

Density of water= 1 kg/L

So, mass of the water:

`Mass\ of\ water=Density * {Volume\ of\ water}`

`Mass\ of\ water=1 kg/L * {1000\ L}`

Mass of water = 1000 kg

Specific heat of water = 4.186 kJ/kg K

ΔT = 10 K

So,

`1000* 4.186* 10=Q`

Q = 41860 kJ

Also, 1 kJ = 1000 J

So, Q = 4.186 × 10⁷ J