Question

Determine the specific volume of superheated water vapor at 15 Mpa and 1000C, using (a) the ideal-gas equation, and (b) the steam tables.

Answer 1

a)
`v=25.56\ kg/m^3`

b)
`v=38.8\ kg/m^3`

Step-by-step explanation:

Given that

Pressure P = 15 MPa

Temperature = 1000 C = 1273 K

a)If assume as ideal gas

The gas constant for super heated steam R is 0.461 KJ/kg.K.

We know that ideal gas equation

P v =RT

15 x 1000 x v =0.461 x 1273

`v=25.56\ kg/m^3`

b) By using steam table

From steam table we can see that volume of super heated vapot at 15 MPa and 1273 K .

`v=38.8\ kg/m^3`