Question

What is the value for the potential energyfor a n = 6 Bohr orbit electron in Joules?

Answer 1

Potential energy for n = 6 Bohr orbit electron is -1.21*10⁻¹⁹J

Step-by-step explanation:

As per the Bohr model, the potential energy of electron in an nth orbit is given as:

`PE_(n) = -(kZe^(2))/(r_(n))`

here:

k = Coulomb's constant = 9*10⁹ Nm2/C2

Z = nuclear charge

e = electron charge = 1.6*10⁻¹⁹ C

r(n) = radius of the nth orbit = n²(5.29*10⁻¹¹m)

Substituting for k, Z(= 1), e and r(n) in the above equation gives:

`PE_(6) = -(9*10^(9)Nm2/C2*1*(1.6*10^(-19)C)^(2))/((6)^(2)*5.29*10^(-11)m)=-1.21*10^(-19)J`