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A town has a 1-million-gallon storage capacity water tower. If the density of water is 62.41b/ft and local acceleration due to gravity is 32.1 ft/s, what is the force in lbf the structural base must provide to support the water in the tower?

User Lwyrn
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1 Answer

4 votes

Answer:


w = 8.316* 10^6 lb

Step-by-step explanation:

force that structural base must be provided with is equal to the weight of water

we know that


\rho =(mass)/(V)


m =\rho V

We know that

w = mg

so we have


w = \rho Vg

density of water is 62.4 lb/ft^3

V = 1 milllion = 100,000 gallons


g = 32.1 ft/s^2


w = 62.4[*10^6 gallons (0.134)/(1 gallon)] [32.1 ft/s^2 (0.3048 m/s^2)/(ft/s^2) (m/s^2)/(9.8 m/s^2)]


w = 8.316* 10^6 lb

User Chi Dov
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