Answer: 38760
Explanation:
Given : The number of employees in the company = 20
The number of employees will be selected by company owner to give bonus = 6
We know that the combination of n things taking r at a time is given by :-
![^nC_r=(n!)/(r!(n-r)!)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/yidrd34ue3ue7nx528yjkzymhqm6gxt7nj.png)
Then, the number of different sets of employees could receive bonuses is given by :-
![^(20)C_6=(20!)/(6!(20-6)!)\\\\=(20*29*18*17*16*15*14!)/((720)14!)=38760](https://img.qammunity.org/2020/formulas/mathematics/college/9c0d42k85wx7lqwb0fegum6s20fvtclv43.png)
Hence, the number of different sets of employees could receive bonuses is 38760.