Question

A pipe of diameter 10 cm carries water at a velocity of 5 m/s. Determine the volumetric flow rate in m'/min (2 pts) a. b. the mass flow rate in kg/min (use the density of water on Thatcher's sheet)

Answer 1

Step-by-step explanation:

It is given that diameter of the pipe is 10 cm which is also equal to
`10 * 10^(-2)m`.

Velocity of water = 5 m/s

(a) Formula to calculate volumetric flow rate is as follows.

Q = Area of the pipe (A) × Velocity of water (V)

=
`(\pi)/(4) * 10 * 10^(-2) * 5 m^(3)/sec`

= 0.039 [/tex]m^{3}/sec[/tex]

=
`(0.039 m^(3)/sec * 60 sec)/(1 min)`

= 2.36
`m^(3) min^(-1)`

Hence, the volumetric flow rate is 2.36
`m^(3) min^(-1)`.

(b) Formula to calculate mass flow rate is as follows.

`Q * \rho`

=
`2.36 m^(3) min^(-1) * 1000 kg m^(-3)`

= 2356.19 kg/min

Therefore, the mass flow rate is 2356.19 kg/min.