Question

A residential heat pump has a coefficient of performance of 1.49 How much heating effect, in kJ/h, will result when 4 kW is supplied to this heat pump?

Answer 1

21.456 kJ/h

Step-by-step explanation:

See the figure attached. In this case

`W_(cycle) = 4 kW`

`Q_(out) = \text{heating effect}`

Coefficient of performance in heat pump is defined by

`COP = (Q_(out))/(W_(cycle))`

`Q_(out) =COP*W_(cycle)`

`Q_(out) =1.49*4 \, W`

`Q_(out) = 5.96 \, W`

Now it is necessary to change units, remember that Watt (W) is defined as J/s

`Q_(out) = 5.96 (J)/(s) (3600s)/(1 h) (1 kJ)/(1000 J)`

`Q_(out) = 21.456 (kJ)/(h)`