189k views
3 votes
A steel band blade, that was originally straight, passes

over8-in.-diameter pulleys when mounted on a band saw. Determine
themaximum stress in the blade, knowing that it is 0.018 in. thick
and0.625 in. wide. Use E = 29 x 106 psi.

1 Answer

3 votes

Answer:


\sigma = 65.25\ ksi

Step-by-step explanation:

given data:

D = 8 inch

R =4 inch

thickness = 0.018 inch

width = 0.625 inch


E =29*10^6 psi

from bending equation we know that


(\sigma)/(y) = (M)/(I) = (E)/(R)


\sigma = (Ey)/(R)

Where y represent distance from neutral axis


y = \frac{t}[2}


y = (0.018)/(2)

y = 0.009inch


\sigma = (29*10^6*0.009)/(4)


\sigma = 65250\ psi


\sigma = 65.25\ ksi

User Justinvf
by
5.2k points