Question

25g of vinegar (a solution containing acetic acid) was addedto

a flask containing an indicator. 37ml of .46M KOH solution wasadded
to the system from a burette to reach the equivalence point.What is
the percentage by mass of vinegar that is aceticacid?

Answer 1

Vinegar has 4.09% of acetic acid.

Step-by-step explanation:

The neutralization reaction is:

`CH_(3)COOH + KOH=>CH_(3)COOK + H_(2)O`

Each mol of KOH reacts with each mole of acetic acid so the quantity of moles of acetic acid is:

`M= 0.46 (mol)/(l)*37ml*(1l)/(1000ml) =0.01702 mol`

The mass of acetic acid is:

0.01702 mol×60.02g/mol=1.0215 g Acetic Acid

Finally, the percentage is:

%=1.0215 g Acetic Acid÷25g vinegar(solution)=4.09%