Question

Which of the following describes what takes place

whensolutions of Pb(NO3)2 and
NH4Clare mixed? Detail the manner in which the
application of thesolubility rules reveal this answer.
A. Pb(NO3)2(aq)
+2NH4Cl(aq)-->NH4NO3(aq)
+PbCl2(s)
B. Pb2++2Cl- --> PbCl2(s)
C. Pb2+(aq) +
2NO3-(aq)+2NH+4(aq)
+2Cl-(aq)-->2NH+4(aq)
+2NO3-(aq) + PbCl2(s)
D. NH+4(aq) +
NO3-(aq)-->2NH4NO32NH4NO3(s)
E. No reaction occurs when the solutions aremixed.

Answer 1

Answer: The correct answer is Option B.

Step-by-step explanation:

The chemical equation for the reaction of lead (II) nitrate and ammonium chloride follows:

`Pb(NO_3)_2(aq.)+2NH_4Cl(aq.)\rightarrow PbCl_2(s)+2NH_4NO_3(aq.)`

Ionic form of the above equation follows:

`Pb^(2+)(aq.)+2NO_3^-(aq.)+2NH_4^+(aq.)+Cl^-(aq.)\rightarrow PbCl_2(s)+2NH_4^+(aq.)+2NO_3^-(aq.)`

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

As, ammonium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

`Pb^(2+)(aq.)+2Cl^-(aq.)\rightarrow PbCl_2(s)`

Solubility rules:

• Chlorides of silver, mercury and lead are insoluble in water. So, they appear as a solid known as precipitate.
• Nitrates of most of the metals are soluble in water. So, they appear as ions in solution.

Hence, the correct answer is Option B.