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A fluid flows through a pipe of constant circular cross-section diameter 1.1m with a mean velocity of 50cm/s. The mass flow rate of the flow through the pipe, given by the formula mass flow rate = (density) (mean velocity) (cross - sectional area), is measured to be 110 kg/s. Find the specific gravity, specific weight and specific volume of the fluid.

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Answer:

Step-by-step explanation:

Given

diameter(d)=1.1 m

mean velocity(u)=50 cm/s

mass flow rate(m)=110 kg/s


A=0.950 m^2


m=\rho \cdot A\cdot u

where
\rho =density of fluid


110=\rho * 0.95* 0.5


\rho =231.46 kg/m^3

Therefore specific gravity
=(\rho )/(\rho _(water))


=(231.46)/(1000)=0.231

Specific weight
=\rho \cdot g=231.46* 9.81=2270.70 kg/m^2-s^2

specific volume
=(1)/(density)


=(1)/(231.46)=0.00432 m^3/kg

User Ulf Jaehrig
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