Question

Calculate hydrochloric acid (umol)in 200 ul of a
0.5173Msolution of acid?

Answer 1

Answer: The moles of hydrochloric acid is
`1.0346* 10^(-4)\mu mol`

Step-by-step explanation:

To calculate the molarity of solution, we use the equation:

`\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}`

Or,

`\text{Molarity of the solution}=\frac{\text{Micro moles of solute}* 10^6}{\text{Volume of solution (in }\mu L)}}`

We are given:

Molarity of solution = 0.5173 M

Volume of solution =
`200\mu L`

Putting values in above equation, we get:

`0.5173M=\frac{\text{Micro moles of HCl}* 10^6}{200\mu L}\\\\\text{Micro moles of HCl}=1.0346* 10^(-4)\mu mol`

Hence, the moles of hydrochloric acid is
`1.0346* 10^(-4)\mu mol`