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Which equations represent the line that is perpendicular to the line 5x - 2y = -6 and passes through the point

(5, -4)? Select three options.
y=-2 X-2
2x +hoy = -10
L2x - 5y = -10
y+ 4 = _{(x - 5)
y- 4 = 5(x+5)

User Zazaeil
by
6.1k points

1 Answer

3 votes

Answer

See below

Explanation:

The given line has equation


5x - 2y =  - 6

The slope intercept form is


y =  (5)/(2) x + 3

The slope of this line is


m = (5)/(2)

The line perpendicular to this line has slope


-  (2)/(5)

If this line passes through (5,-4), the point-slope form is


y + 4 =  -  (2)/(5) (x  - 5)

The slope-intercept form is


y =  -  (2)/(5) x- 2

The standard form is

2x+5y=-10

User Jason Martin
by
6.3k points