Question

If an elevator is to raise a 5000 lb a height of 30 ft in 320 seconds, what horsepower motor would be required?

Answer 1

Force will be equal to 0.08522 horsepower

Step-by-step explanation:

We given weight of elevator = 5000 lb

Height of the elevator = 30 ft

Time t = 320 sec

We have to calculate the power in horsepower

For let first find power in lb-ft/sec

So power in lb-ft/sec
`=(5000lb* 30ft)/(320sec)=46.875lb-ft/sec`

Now we know that 1 horsepower = 550 lb-ft/sec

So 46.785 lb-ft/sec =
`(46.875)/(550)=0.08522horsepower`