Question

Final Temperature in Heating Applesauce. A mixture of 454 kg of applesauce at 10°C is heated in a heat exchanger by adding 121300 kJ. Calculate the outlet tem perature of the applesauce. (Hint: In Appendix A.4, a heat capacity for applesauce is given at 32.8C. Assume that this is constant and use this as the average com)

Answer 1

`T_f = 76.46°C`

Step-by-step explanation:

Given data:

Mass of mixture = 454 kg

Initial temperature is 10°C

Heat added is Q = 121300 kJ

Heat capacity (Applesuace) at 32.8°C is 4.02kJ/kg K

From heat equation we have

`Q = mCp(T_f -T_i)`

`(Q)/(mCp) = (T_f -T_i)`

`T_f = T_i + (Q)/(mCp)`

Putting all value to get required final temperature value

`T_f = (121300)/(454* 4.02) + 10`

`T_f = 76.46°C`