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Show that if A and B are similar nxn matrices, then det(A)=det(B).

User Seffy
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1 Answer

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Explanation:

To prove it we just use the definition of similar matrices and properties of determinants:

If
A,B are similar matrices, then there is an invertible matrix
C, such that
A=C^(-1)BC} (that's the definition of matrices being similar). And so we compute the determinant of such matrix to get:


det(A)=det(C^(-1)BC)=det(C^(-1))det(B)det(C)


=(1)/(det(C))det(B)det(C)=det(B)

(Determinant of a product of matrices is the product of their determinants, and the determinant of
C^(-1) is just
(1)/(det(C)))

User Nuttysimple
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