Question

Two cars leave a city heading in the same direction. After 3 hours, the faster card is 9 miles ahead of the slower car. The slower car has traveled 153 miles. Find the speed of the two cars.

Answer 1

The speed of the slower car is: 51 miles/hour and the speed of the faster car is 54 miles/hour.

Explanation:

First, we can easily find the speed of the slower car, since we know that the speed is given by the formula v=d/t, where d stands for the traveled distance and t for the elapsed time.

`v_(s)=(d_(s))/(t)=(153\ miles)/(3\ hours) = 51\ miles/hour`

Next, for the faster car, we know that the distance traveled is 153+9 miles in the same time, therefore, its speed is given by:

`v_(f)=(d_(f))/(t)=(153+9\ miles)/(3\ hours) = 54\ miles/hour`