Question

In this experiment it takes about 6 microliters of solution

toproduce a spot 8mm in diameter. If the Cu(NO) solution
containsabout 6g Cu^2+ per liter how many micrograms of Cu^2+ ion
are therein one spot?

Answer 1

36 micrograms of
`Cu^(2+)` ion are therein one spot.

Step-by-step explanation:

Amount of copper(II) ions in 1 liter solution = 6 g

Volume of solution used in spotting = 6μL =
`6* 10^(-6) L`

`1 \mu L = 10^(-6) L`

Amount of copper (II) ion in
`6* 10^(-6) L`:

`6* 6* 10^(-6) L=3.6* 10^(-5) g`

`1 g = 10^(6) \mu g`

`3.6* 10^(-5) g=3.6* 10^(-5)* 10^(6) \mu g=36 \mu g`

36 micrograms of
`Cu^(2+)` ion are therein one spot.