Question

Polygon ABCD is translated to create polygon A'B'C'D'. Point A is located at (1,5) os located at (-2,1). What is the distance from B to B'?

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Answer 1

The distance from B to B' is 5 units

Explanation:

The complete question is

Polygon ABCD is translated to create polygon A'B'C'D'. Point A is located at (1,5) and point A' is located at (-2,1). What is the distance from B to B'?

we know that

In a translation the figure maintains its dimensions and internal angles

so

AA'=BB'=CC'=DD'

The distance BB' is the same that the distance AA'

Find the distance AA'

the formula to calculate the distance between two points is equal to

`d=\sqrt{(y2-y1)^(2)+(x2-x1)^(2)}`

we have

A(1,5),A'(-2,1)

substitute in the formula

`AA'=\sqrt{(1-5)^(2)+(-2-1)^(2)}`

`AA'=\sqrt{(-4)^(2)+(-3)^(2)}`

`AA'=√(25)`

`AA'=5\ units`

therefore

The distance from B to B' is 5 units