Question

Iliana multiplied 3p – 7 and 2p2 – 3p – 4. Her work is shown in the table. The expression (3 p minus 7)(2 p squared minus 3 p minus 4) is shown above a table with 3 columns and 2 rows. First column is labeled 2 p squared, second column is labeled negative 3 p, the third column is labeled negative 4. First row is labeled 3 p with entries 6 p cubed, negative 9 p squared, negative 12 p. Second row is labeled negative 7 with entries negative 14 p squared, 21 p, 28. Which is the product? 6p3 + 23p2 + 9p + 28 6p3 – 23p2 – 9p + 28 6p3 – 23p2 + 9p + 28 6p3 + 23p2 – 9p + 28

Answer 1

the answer is C

Explanation:

Answer 2

The correct option is C)
`6p^3-23p^2+9p+28`

Explanation:

Consider the provided expression.

`3p - 7` and
`2p^2 - 3p - 4`

According to the provided information the table will be like this.

`2p^2` -3p -4

3p
`6p^3` -9p² -12p

-7
`-14p^2` 21 p 28

The above table shows the terms after multiplication.

To find the product you just need to add the terms as shown.

`6p^3-9p^2-12p-14p^2+21p+28`

`6p^3-9p^2-14p^2-12p+21p+28`

`6p^3-23p^2+9p+28`

Hence, the product is
`6p^3-23p^2+9p+28`.

You can verify this by product as shown.

`3p-7(2p^2-3p -4)`

`6p^3-9p^2-12p-14p^2+21p+28`

`6p^3-23p^2+9p+28`

Hence, the correct option is C)
`6p^3-23p^2+9p+28`