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Solve a+b=9; 2b+2c=13; 2a-c=11 unknowly

1 Answer

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Answer: a = 17/2 and b =1/2 and c = 6

Explanation:

the system is : a+b=9...........(1)

2b+2c=13 .......(2)

2a-c=11 ...........(3)

by (1) and (2) calculate : a and b

by (3) : 2a = 11 +c

so : a = (11+c)/2.....( *)

by (2) : 2b = 13 -2c

so : b =(13-2c)/2......(**)

put the value for a and b by (*) and (**) in (1) :

(11+c)/2. + (13-2c)/2 = 9

(11+c +13-2c)/2 = 9

24-c =18

c = 24-18

c = 6

put this value in (*) and (**)

a = (11+6)/2

a = 17/2

b = (13-12)/2

b =1/2

yoi can verify : 1) a+b = 9 : 17/2 +1/2 = 18/2 = 9 .....right

2) 2b+2c=13 : 2(1/2)+2(6) =1+12 = 13 .....right

3) 2a-c=11 : 2(17/2)-6 =17-6 = 13.......right

User Bastien Robert
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