Question

Va box contains 4 red marbles and 7 green remove 3 at once probability of 3 red

Answer 1

0.024

Explanation:

Given,

Red marbles = 4,

Green marbles = 7,

Total marbles = 4 +7 = 11,

Ways of choosing 3 marbles =
`^(11)C_3`

Ways of choosing 3 red marble =
`^4C_3`

Hence, the probability of 3 red marble =
`(^4C_3)/(^(11)C_3)`

`=((4!)/(3!1!))/((11!)/(3!8!))`

`=(4)/(165)`

≈ 0.024