Question

A pharmacist weighed 475 mg of a substance on a balance of dubious accuracy. When checked on a balance of high accuracy, the weight was found to be 445 mg. Calculate the percentage error in the first weighing.

Answer 1

Answer: 6.416%

Explanation:

The percentage error formula is given by :-

`\%\text{error}=\frac{|\text{Estimate-Actual}|}{\text{Actual}}*100`

Given : The estimated weight of a substance = 475 mg

The actual weight of the substance = 445 mg

Then,

`\%\text{error}=(| 475-445|)/(445)*100\\\\=(30)/(445)*100=6.74157303371\approx6.416\%`

Hence, the percentage error in the first weighing. = 6.416%