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A liquid oral concentrate of morphine sulfate contains 2.4 g of morphine sulfate in a 120-mL bottle. Calculate the concentration of morphine sulfate on a mg/mL basis.

User Dakab
by
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2 Answers

3 votes

Answer:

Explanation:

A liquid oral concentrate of morphine sulfate contains 2.4 g of morphine sulfate in-example-1
User Tomas Smagurauskas
by
7.1k points
1 vote

Answer:

20 mg/ml.

Explanation:

We have been given that a liquid oral concentrate of morphine sulfate contains 2.4 g of morphine sulfate in a 120-mL bottle.


\text{Concentration of morphine sulfate on g/mL basis}=\frac{\text{2.4 g}}{\text{120 ml}}

To convert the concentration of morphine sulfate on a mg/mL basis, we need to convert 2.4 grams to milligrams.

1 gram equals 1000 milligrams.


\text{Concentration of morphine sulfate on mg/mL basis}=\frac{\text{2.4 g}}{\text{120 ml}}*\frac{\text{1,000 mg}}{\text{1 g}}


\text{Concentration of morphine sulfate on mg/mL basis}=\frac{2.4*\text{1,000 mg}}{\text{120 ml}}


\text{Concentration of morphine sulfate on mg/mL basis}=\frac{2400\text{ mg}}{\text{120 ml}}


\text{Concentration of morphine sulfate on mg/mL basis}=\frac{20\text{ mg}}{\text{ml}}

Therefore, the concentration of morphine sulfate would be 20 mg per ml.

User Robert Sanders
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