Question

A boy has 8 red marbles, 2 blue marbles 7 yellow and 3 green. what is the probability for selecting a red marble AND then selecting a green marble?

Answer 1

Answer: Our required probability is
`(11)/(20)`

Explanation:

Since we have given that

Number of red marbles = 8

Number of blue marbles = 2

Number of yellow marbles = 7

Number of green marbles = 3

So, Total number of marbles = 8 + 2 + 7 + 3 = 20

So, Probability for selecting a red marble and then selecting a green marbles is given by

P(red) + P(green) is equal to

`(8)/(20)+(3)/(20)\\\\=(8+3)/(20)\\\\=(11)/(20)`

Hence, our required probability is
`(11)/(20)`