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Find all relative extrema and inflection points for fx)=(2x+7)^4

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Answer:


x=-(7)/(2) Extrema point.

The function does not have inflection points.

Explanation:

To find the extrema points we have:


f'(x)=0

Then:


f(x)=(2x+7)^4


f'(x)=4(2x+7)^3(2)


f'(x)=8(2x+7)^3

Now:


f'(x)=8(2x+7)^3=0


8(2x+7)^3=0


(2x+7)^3=0


2x+7=0


2x=-7


x=-(7)/(2)

To find the inflection points we need to calculate
f''(x)=0 but due to that que have just one extrema point, the function does not have inflection points.

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