Answer:
a) 213.3 mg/L
b) 62.61 mg/L
c) 0.0225 mg/L
Step-by-step explanation:
Theoretical oxygen demand (ThOD)is essentially the amount of oxygen required for the complete degradation of a given compound into the final oxidized products
a) Given:
Concentration of acetic acid,
= 200 mg/L
![CH3COOH + 2O2 \rightarrow 2CO2 + 2H2O](https://img.qammunity.org/2020/formulas/chemistry/college/axc27v3g6s9q0uyq4qeamnk2pck9poa6s9.png)
![ThOD = (mass\ O2)/(mass\ CH3COOH) * conc. CH3COOH](https://img.qammunity.org/2020/formulas/chemistry/college/ckwz3kco6u542n9xnx6p6dnr97ufaff798.png)
Based on the reaction stoichiometry:
mass of
= 60 g
mass of
= 2(32) = 64 g
![ThOD = (64 g)/(60 g) * 200mg/L = 213.3 mg/L](https://img.qammunity.org/2020/formulas/chemistry/college/5dpyc0sgfn4j9278tjaa4e13rnn4kqwbf6.png)
b) Given:
Concentration of ethanol,
= 30 mg/L
![C2H5OH + 3O2 \rightarrow 2CO2 + 3H2O](https://img.qammunity.org/2020/formulas/chemistry/college/w4lbsqete7b61zzys12knj79xh9l1uv6u3.png)
![ThOD = (mass\ O2)/(mass\ C2H5OH) * conc. C2H5OH](https://img.qammunity.org/2020/formulas/chemistry/college/ebqbyaj6gujcf4p099cgt49fbqpe1tdrar.png)
Based on the reaction stoichiometry:
mass of
= 46 g
mass of
= 3(32) = 96 g
![ThOD = (96 g)/(46 g) * 30mg/L = 62.61 mg/L](https://img.qammunity.org/2020/formulas/chemistry/college/vcze86auovy80yhy6w2hv59ryxz2m85ftt.png)
c) Given:
Concentration of sucrose,
= 50 mg/L
![C12H22O11 + 12O2 \rightarrow 12CO2 + 11H2O](https://img.qammunity.org/2020/formulas/chemistry/college/doyb6qr7ydnc60sfwnm86ukavye5tdcyn9.png)
![ThOD = (mass\ O2)/(mass\ C22H22O11) * conc. C12H22O11](https://img.qammunity.org/2020/formulas/chemistry/college/tf47aohd7h9sti926vjxem9bsgzhfe4i4r.png)
Based on the reaction stoichiometry:
mass of
= 342 g
mass of
= 12(32) = 384 g
![ThOD = (384 g)/(342 g) * 50mg/L = 0.0225 mg/L](https://img.qammunity.org/2020/formulas/chemistry/college/zm0p491ml6d92q8pth7zu8zzewbdi8m61n.png)