Question

PLS HELP ASAP 7. A dog runs around on a track and its owner measures its position every second for 8 seconds. Plot the data in the

table on the axis given below. Label the x axis "time" and the y axis "Position" and put the appropriate number
and units on the axis.

Answer 1

(a) 0-2 seconds and 3-6 seconds

(b) 2-3 seconds and 7-8 seconds

(c) 6-7 seconds

(d) 13.33 m/s (2 d.p.) foward

Step-by-step explanation:

See the attached graph for the plot of the given data.

Part (a)

The dog is moving forward between 0 - 2 seconds and 3 - 6 seconds because as time is increasing the position is increasing.

Part (b)

The dog is standing still between 2 - 3 seconds and 7 - 8 seconds because as time is increasing the position stays the same.

Part (c)

The dog is moving backwards between 6 - 7 seconds because as time is increasing the position is decreasing.

Part (d)

`\boxed{\sf Speed=(Distance)/(Time)}`

To find the average velocity between 3 - 6 seconds, divide the difference in position at these times by the difference in seconds:

`\sf Average\:velocity=(60-20)/(6-3)=(40)/(3)=13.33\:m/s \: (2\:d.p.)\:forward`

Answer 2

Answers / Explanation:

1. Write the scale of time on the x axis (horizontal axis) and the position on the y axis (vertical axis).

(Check the attached image to see how the finished graph should look like).

a. During which time period(s) is the dog moving forward? How can you tell?

To determine these answers, analyze the graphic and find out the intervals of time when the y value was increasing.

From time= 0s to time = 2s; from time= 3s to time = 6s. We can affirm this because the graph had a positive slope, and the y value (which is the position) was increasing.

b. During which time period(s) is the dog standing still? How can you tell?

The dog is standing still from time= 2s to 3s and from time= 7s to 8s. We can affirm this because time passed and the position didn't increase or decrease in these parts of the graph.

c. During which time period(s) is the dog moving backwars? How can you tell?

For this question, apply the same logic applied in question "a", except that this time we are looking for the intervals where the y value decreases.

From time=6s to time= 7s the dog was moving backwards, because time passed and the y axis (position) decreased.

d. What is the dogs average velocity during the time-period of 3-6 seconds? (ans: 13.33 m/s Forward)

For this question, use the average velocity formula:
`a_v=(p_2-p_1)/(t_2-t_1)`;where
`p_2` is the final position of the dog,
`p_1` is the initial position,
`t_2` is the time at position 2 and
`t_1` is the time at position 1.

Get the values from the graph and substitute in the formula:

`a_v=((60m)-(20m))/((6s)-(3s))=(40m)/(3s) =13.33m/s.`