Question

Solid

Substance A has a melting point of 100°C.
Liquid Substance B has a freezing point of
110°C. For each substance, identify its state
of matter, and describe the motion of its
particles, when the substance is at 115°C.

Answer 1

melting point and the freezing point are the same things.

so both the substance will be in liquid state.

the particles will be able to move somewhat but not as much as the particles in gas phase.

substance A particles will show same amount of motion as the particles of substance B because the temperature of A and B is same and they will posses same Kinetic energy as the formula for Kinetic energy is :-

KE = 3/2 × (boltzman constant) × temperature of substance

but their potential energies will differ substance A will have more potential energy than substance B because the temperature of A is more than the temperature of B.

PLEASE TELL IF IT IS RIGHT OR WRONG.

Answer 2

Both substance A and B will be at liquid state at 115 degree Celsius.

Step-by-step explanation:

Substance A

Melting point of substance A is 100 degree Celsius. Thus, temperature higher than 100 degree will result into liquid substance A. Thus at 115 degree Celsius, substance A is liquid and the particle will be free enough to move and slide over each other.

Substance B

The freezing point of substance B is 110 degree Celsius. This means that for any temperature higher than 110 degree Celsius, substance B will occur in liquid state. The particles of solution B at liquid state will also be free enough to move and slide over each other.