Question

2(2X-3)-10 <_ 6(X-2)

Answer 1

`\large\boxed{x\geq-2\to x\in[-2,\ \infty)}`

Explanation:

`2(2x-3)-10\leq6(x-2)\qquad\text{use the distributive property}\ a(b+c)\\\\(2)(2x)+(2)(-3)-10\leq(6)(x)+(6)(-2)\\\\4x-6-10\leq6x-12\\\\4x-16\leq6x-12\qquad\text{add 16 to both sides}\\\\4x\leq6x+4\qquad\text{subtract}\ 6x\ \text{from both sides}\\\\-2x\leq4\qquad\text{change the signs}\\\\2x\geq-4\qquad\text{divide both sides by 2}\\\\x\geq-2`

Answer 2

x<14/5

Explanation:

expand

4x-6-10 < -6x+12

4x-16 < -6x+12

4x < -6x+12+16

4x < -6x+28

4x+6x < 28

10x < 28

x < 28/10

hope this helps