Question

5. A grocer wishes to mix two kinds of nuts costing

$2.41 per pound and $3.65 per pound to make a
248 pounds of mixed nuts costing $2.51 per pound.
To determine the number of pounds of the $2.41
per pound nuts in the mixture, solve for x in the
equation 2.41x +3.65(248 - x) = 622.48. How
many pounds of the $2.41 per pound nuts should
included in the mixture?​

Answer 1

Ans:

The solve for x:

2.41x+3.65(248-x)=622.48

2.41x+3.65×248-3.65x=622.48

2.41x-3.65x+905.2=622.48

-1.24x=622.48-905.2

-1.24x= -282.72

x= -282.72÷ -1.24

x=228

Pounds of nuts nper pound $2.41should be included:

228× $2.41

=549.48

Hope it Helps!