Question

A 10.0cm3 volume of alcohol has a mass of 7.05g. What the density

Answer 1

A 10.0cm3 volume of alcohol has a mass of 7.05g.
`0.705 (g)/(c m^(3))` is the density

Answer:
`0.705 (g)/(c m^(3))`

Step-by-step explanation:

The ratio between the mass of a substance and its unit volume is referred as density.

`\text {Density}=\frac{\text { mass }}{\text { volume }}=\frac{7.05 g}{10.0 \mathrm{cm}^(3)}=0.705 \frac{g}{\mathrm{cm}^(3)}` is the Answer

Note:

1000 g = 1 kg

100 cm = 1 m

When we used to transform the given values into S.I units, then

`\text {Density}\left((k g)/(m^(3))\right)=\frac{\text {Mass}(k g)}{\text {Volume}\left(m^(3)\right)}`

Alcohol’s volume can be written as,
`10.0 c m^(3) = 10 * 10^(-2) m^(3)`

Alcohol’s mass can denote as,
`7.05 g = 7.05 * 10^(-3) \mathrm{kg}`

Then,
`\text { Density }\left((k g)/(m^(8))\right)=(, 00705(k g))/(0.1\left(m^(3)\right)) = .0705 \frac{\mathrm{kg}}{\mathrm{m}^{\mathrm{s}}}`