Question

1) A 25 μL diluted sample (1:25) of protein was added to 2 ml of Bradford reaction assay tube. The absorbance at 595 was 0.75 and according to a BSA standard curve corresponding to 0.025 mg protein on the x-axis. What is the protein concentration (mg/ml) of the original protein?

Answer 1

protein concentration
`= 2.5* 10^(-5) mg/ml`

Step-by-step explanation:

from the given information

total amount of protein is 0.025 mg

amount of dilute solution is
`25\mu L`

Therefore original concentration is given as

original concentration
`=(0.025 mg)/(25 \mu L) = 0.001 mg/\mu L`

`= 0.001 mg/\mu L * 25`

HERE 25 is dilution factor

`= 0.025 mg/\mu L`

convert
`mg/\mu L\  to\ mg/ml = 0.025 mg/\mu\ L * (1)/(10^3 \mu\  L)`

`= 2.5* 10^(-5) mg/ml`