2 Answers

Andrew Cullen · Answer 1 · 2020-12-19T18:29:45+0000

Answer:

20 square units

Explanation:

we know that

The area of rectangle is equal to

A=LW

In this problem

$L=WX=ZY\\W=WZ=XY$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^(2)+(x2-x1)^(2)}$

Find the distance WX

we have

W(-3,1), X(3,3)

substitute the values in the formula

$d=\sqrt{(3-1)^(2)+(3+3)^(2)}$

$d=\sqrt{(2)^(2)+(6)^(2)}$

$d_W_X=√(40)\ units$

Find the distance XY

we have

X(3,3),Y(4,0)

substitute the values in the formula

$d=\sqrt{(0-3)^(2)+(4-3)^(2)}$

$d=\sqrt{(-3)^(2)+(1)^(2)}$

$d_X_Y=√(10)\ units$

Find the area of rectangle

A=(WX)(XY)

substitute the values

$A=(√(40))(√(10))=20\ units^2$

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