Question

Enter an inequality that represents the graph in the box.


Help please?

Answer 1

Explanation:

Easy. its
`x^(2) \int\limits^a_b {x} \, dx \\ \\ \left \{ {{y=2} \atop {x=2}} \right. \\ \\eq (x)/(y) \beta \al\left \{ {{y=2} \atop {x=2}} \right. pha \\eq \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \geq \\ \left \{ {{y=2} \atop {x=2}} \right. \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]`

Answer 2

The inequality that represents the graph is:

`y\geq x+3`

Explanation:

By looking at the graph we observe that the graph is a solid line which passes through the point (-1,0) and (1,2).This means that the inequality is a inequality with a equality sign(i.e. not strict)

This means that the equation of line is:

`y-2=(2-0)/(1-(-1))* (x-(-1))\\\\y-2=(2)/(2)* (x+1)\\\\y-2=x+1\\\\y=x+1+2\\\\y=x+3`

The shaded region is away from the origin.

This means that the inequality does not pass the zero test.

Hence, the inequality is:

`y\geq x+3`