Answer with explanation:
Given : Sample size : n= 16
Degree of freedom = n-1=15
The obtained t-statistic value = 1.94
Since, The treatment is expected to increase scores and the sample mean shows an increase.
Let
be the population mean before and
denotes the population mean after the treatment.
then the related hypothesis will be :-
![\text{Null hypothesis }H_0:\mu_0=\mu\\\\\text{Alternative hypothesis } H_1:\mu_0<\mu](https://img.qammunity.org/2020/formulas/mathematics/high-school/dgurjjsnm8cq8bg6v56e19037sjnhku6mk.png)
Since the alternative hypothesis is left-tailed, so the test is a left tailed test.
The critical value for
=1.753
Since, the obtained value (1.94) is greater than the critical value (1.753) so we reject the null hypothesis .
Therefore, we have enough evidence to support the alternative hypothesis.
Hence, we conclude that treatment may successful to increase scores and the sample mean shows an increase.