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15 votes
find the mass of water that has a specific heat of 4.18 J/g C that requires 1500 J of energy to go from 33C to 113 C

User SimperT
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1 Answer

23 votes
23 votes

Answer:

4.49 g

Step-by-step explanation:

To find the mass of water, you need to use the following equation:

Q = mcΔT

In this equation,

-----> Q = energy (J)

-----> m = mass (g)

-----> c = specific heat (J/g°C)

-----> ΔT = change in temperature (°C)

You can plug the given values into the equation and solve for "m".

Q = 1,500 J c = 4.18 J/g°C

m = ? g ΔT = 113°C - 33°C = 80°C

Q = mcΔT <----- Specific Heat Equation

1,500 J = m(4.18 J/g°C)(80°C) <----- Insert values

1,500 J = m(334.4) <----- Multiply 4.18 and 80

4.49 = m <----- Divide both sides by 334.4

User Jonas Lundgren
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